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Things take time

[SWIFT] URL형식으로 된 String에서 Parameter 추출

func getQueryStringParameter(url: String, param: String) -> String? { guard let url = URLComponents(string: url) else { return nil } return url.queryItems?.first(where: { $0.name == param })?.value } [예시] print("[Gyeom] :: \(getQueryStringParameter(url: "https://g-y-e-o-m.tistory.com/manage/newpost/?type=post&returnURL=%2Fmanage%2Fposts%2F", param: "returnURL")"
iOS (기능) 2021. 11. 19. 13:21
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